The first is replaced before the second is drawn.
A bag of marbles contains 120 red and yellow marbles.
The number of yellow marbles is 1 more than 2 times the number of red marbles.
P 3 10 7 9 2 8 p 7 120 since we were ask to find the probability of chosing 1 red 1 black and 1red marble without replacement after each draw we can use the fundamental method in finding the probability.
A random variable assigns the number of red marbles to each outcome.
Thus the probability of choosing the second red marble is 4 11.
Asked by lyla on april 18 2014.
A bag contains 120 marbles.
The probability of consecutively choosing two red marbles and a green marble without replacement.
If lisa draws a random marble from the bag what is the probability that it will be a red green or blue marble.
A bag contains nine red marbles four green marbles three blue marbles and two yellow marbles.
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There are 114 red marbles in the bag.
Calculate the expected value of the random variable.
There are 3 red marbles and 7 black ma.
The probability of choosing first red marble is 5 12 because there is not any replacement now 4 red marbles are remained and totally 11 marbles.
Asked 03 10 20 a bag contains yellow marbles and red marbles 16 in total.
A bag contains 4 yellow 2 red and 6 green marbles.
By dividing both sides by the common factor 40.
Y number of black marbles.
Which can be re expressed as.
2 put value of x in 1 we get put y 6 in 2 we get hence there are 114 red marbles in the bag.
A handful of 5 marbles is grabbed from the bag.
The number of different handfuls of 5 marbles with exactly 2 green and no yellow marbles is.
A bag contains 9 red marbles 8 white marbles and 6 blue marbles.
Two marbles are drawn.
1 there are 19 red marbles every for black marble.
A bag contains 70.
The ratio between blue and red marbles is therefore.