And then there s one blue marble in the bag.
A bag of marbles contains 12 red marbles 8 blue.
So i could pick that green marble or that green marble.
Two consecutive draws are made from the bag without replacement of the first draw.
So this is all the possible outcomes.
So i could pick that red marble or that red marble.
Given that you have bb.
Solution for a bag contains 7 red marbles 6 white marbles and 8 blue marbles.
There are 55 marbles 25 of which are not red p getting a color other than red p 25 55 455 probability of this happening 3 times in a row is.
Probability examples a jar contains 30 red marbles 12 yellow marbles 8 green marbles and 5 blue marbles what is the probability that you draw and replace marbles 3 times and you get no red marbles.
A bag contains 3 red marbles 5 green marbles and 2 blue marbles.
You have 8 6 4 18 marbles each assumed to have a 1 18 probability of being drawn.
There are 8 6 48 ways of drawing blue then red so p 8 6 18 18 4 3 9 9 4 3 9 4 27 0 148148148 or just under 15.
There s one blue marble.
These are clearly all yellow.
You have an 8 12 2 3 chance of picking a green marble the first time and a 4 12 1 3 chance of not picking green the first time.
A bag contains eight green marbles and four blue marbles.
There s two red marbles in the bag.
You draw 3 marbles out at random without replacement.
A bag contains 3 red marbles and 4 blue marbles.
A marble is taken at random and replaced.
There s two green marbles in the bag.
A bag contains eight green marbles and four blue marbles.
The problem asks for the probability of rr or bb.
Another marble is taken from the bag.