For water specific heat 4 18 j g degrees celsius and for granite specific heat 0 79 j g degrees celsius.
A 12 5 g sample of granite initially at 82.
B 1 55 10 3 0 c.
What is the final temperature of both substances when they reach thermal equilibrium.
What is the final temperature of both substances when they reach thermal equilibrium.
What is the final temperature of both substances when they reach thermal equilibrium.
A 12 5 gram sample of granite initially at 82 0 oc is immersed into 25 0 grams of water initially at 22 0 oc.
D 27 2 0 c.
For water c s 4 18 j g c and for granite c s 0 790 j g c a.
For water c s 4 18 j g 0 c and for granite c s 0 790 j g 0 c.
For water cs 4 18j g c and for granite cs 0 790j g c.
What is the final temperature of both substances when they reach thermal equilibrium.
1 55 10 3 c c.
A 12 5 g sample of granite initially at 82 0 c is immersed in 25 0 g of water initially at 22 0 c.
A 13 0 g sample of granite initially at 82 0 o c is immersed into 26 0 g of water initially at 23 0 o c.
We will assume m 5 kg.
For water c p 4 18 j g o c and for granite c p 0 790 j g o c.
What is the final temperature of both substances when they reach thermal equilibrium.
For water cs 4 18j g c and for granite cs 0 790j g c.
Let s say we want to cool the sample down by 3 degrees.
In our example it will be equal to c 63 000 j 5 kg 3 k 4 200 j.
A 14 0g sample of granite initially at 77 0 c is immersed into 22 0g of water initially at 22 0 c.
Determine the mass of the sample.
What is the final temperature of both substances when they reach thermal equilibrium.
You can also go to advanced mode to type the initial and final values of temperature manually.
Calculate specific heat as c q mδt.
What is the final temperature of both substances when they reach thermal equilibrium.
A 12 5 g sample of granite initially at 82 0 0 c is immersed into 25 0 g of water initially at 22 0 0 c.
A 12 5 g sample of granite initially at 82 0oc is immersed into 25 0 g of water initially at 22 0oc.
For water cs 4 18 j oc g and for granite cs 0 790 j oc g.
The answer to a 12 5 g sample of granite initially at 82 0 0c is immersed into 25 0 g of water initially at 22 0 0c.
Then δt 3 k.
For water cs 4 18 j g 0c and for granite cs 0 790 j g 0c.
For water cs 4 18 j g oc and for granite cs 0 790 j g oc.
A 52 0 0 c.
C 15 7 0 c.
A 12 5 g sample of granite initially at 82 degrees celsius is immersed into 25 g of water initially at 22 degrees celsius.